Question

split the middle term of 2x² - 2√2x -3 ?

Answer 1

Hello friend

Good morning

Your answer is given below :

$= > 2 {x}^{2} - 2 \sqrt{2} x - 3 \\ \\ = > 2 {x}^{2} - 3 \sqrt{2} + 1 \sqrt{2}x - 3 \\ \\ = > \sqrt{2} x \: ( \sqrt{2} x - 3) + 1( \sqrt{2} x - 3) \\ \\ = > ( \sqrt{2 } x + 1)( \sqrt{2} x -3) \\ \\ = > x \: = \frac{ - 1}{ \sqrt{2} } \: and \: \frac{3}{ \sqrt{2} }$


I hope it will help you a lot

Thanks have a good day

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Answer 2

x= 1/√2 and x=-3/√2

Split the middle term of 2x² - 2√2x -3 ?

$2 {x}^{2} - (3 \sqrt{2x} - \sqrt{2x} ) - 3 \\ 2 {x}^{2} - 3 \sqrt{2x} \: \: \: \: \: \: - \sqrt{2x} - 3 \\ \: \sqrt{2x} ( \sqrt{2x} + 3) \: \: \: \: - 1( \sqrt{2x} + 3) \\ factors \: are = > \\ (\sqrt{2x} + 3) \: \: \: \: \: \: \: \: \: \: \: ( \sqrt{2x} - 1) \\ \\ \\ when \: \: \: \: \sqrt{2x} - 1 = 0 \\ \sqrt{2x} = 1 \\ x = \frac{1}{ \sqrt{2} } \\ \\ \\ when \: \: \: \sqrt{2x } + 3 = 0 \\ \sqrt{2x } = - 3 \\ x = \frac{ - 3}{ \sqrt{2} }$