Question

split the middle term of
$2 \sqrt{3} {x}^{2} - 5x + \sqrt{3}$
​

Answer 1

$\huge{\boxed{\texttt{Answer :- }}}$

♦ In the question above it's asked to split the middle term , well as to be compleat It should be "Split the middle term and factorise "

♦ We have to split the middle term in order to get the number by which we can factorise the above polynomial .

♦ Splitting the middle term

$2\sqrt{3}x^2 - 5x + \sqrt{3}$

$= 2\sqrt{3}x^2 -3x -2x +\sqrt{3}$

♦ Now as we have splited the middle term , then now we will be grouping it .

$= 2\sqrt{3}x^2 -3x - 2x +\sqrt{3}$

$=\sqrt{3}x(2x - \sqrt{3}) -1(2x - \sqrt{3} )$

$= (2x - \sqrt{3})(\sqrt{3}x - 1)$

♦ Well after Splitting and factorization we get

$(2x - \sqrt{3})(\sqrt{3}x - 1)$

♦ From above we can get the value of x for which the polynomial becomes zero ( or the zero of the polynomial)

>> Well the zeros are

$\dfrac{\sqrt{3}}{2}$ and $\dfrac{1}{\sqrt{3}}$