Math, asked by silu2004, 1 year ago

split the middle term
 {x}^{2}  - 11x + 42


himani22mahendr: x^2 - (14-3)x +42
himani22mahendr: X^2 -14x +3x +42
himani22mahendr: x(x+3) -14 (x+3)
himani22mahendr: (x-14) (x+3)
himani22mahendr: x= 14,-3

Answers

Answered by MarkAsBrainliest
21
\bold{Answer :}

Now,

x² - 11x - 42

= x² - (14 - 3)x - 42

= x² - 14x + 3x - 42

= x (x - 14) + 3 (x - 14)

= (x - 14) (x + 3),

which is the required factorization.

#\bold{MarkAsBrainliest}

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Answered by Anonymous
27
Hey Friends!!

Here is your answer↓⬇

Note :- Your question have some error , the right question is like that:-)


 \huge \bf \:  {x}^{2}  - 11x - 42.


▶⏩ So, Now


 \boxed{Factorising  \: by  \: spilting  \: the \:  middle \:  term.}

 \bf =  {x}^{2}  - 11x - 42.


 \bf =  {x}^{2}  - 14x + 3x - 42.


 \bf = x(x - 14) + 3(x - 14).


 \huge = (x + 3)(x - 14).


✅✅ Hence, it is factorised ✔✔.



 \huge \boxed{THANKS}


 \huge \bf \underline{Hope  \: it \:  is  \: helpful  \: for  \: you}

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