Question

Split the middle terms
1/4x^2-2x+3

Answer 1

Answer:

1/4 x^2-2x+3

=1/4(x^2-8x+12)

=1/4(x^2-6x-2x+12)

=1/4{x(x-6)-2(x-6)}

=1/4(x-6)(x-2)

Answer 2

ANSWER:

To Factorize:

• 1/4x² - 2x + 3

Solution:

$\text{We are given that,}\\\\:\longrightarrow\dfrac{1}{4}x^2-2x+3\\\\\text{Taking LCM,}\\\\:\implies\dfrac{x^2-4(2x)+4(3)}{4}\\\\:\implies\dfrac{x^2-8x+12}{4}\\\\\text{Splitting 8x into 6x and 2x,}\\\\:\implies\dfrac{x^2-6x-2x+12}{4}\\\\\text{Taking common,}\\\\:\implies\dfrac{x(x-6)-2(x-6)}{4}\\\\\text{Taking (x - 6) common,}\\\\:\implies\dfrac{(x-6)(x-2)}{4}\\\\\bf{:\implies\dfrac{1}{4}(x-6)(x-2)}$