Question

Spliting the middle term x²+6x-7​

Answer 1

Completing the square method:

x  

2

+6x=7

Adding [  

2

1

​

×coefficient ofx]  

2

 both sides we get,

x  

2

+6x+[  

2

1

​

×6]  

2

=7+[  

2

1

​

×6]  

2

 

or, x  

2

+6x+3  

2

=7+3  

2

 

or, (x+3)  

2

=16

or, x+3=  

16

​

 

or, x+3=±4

or, x=4−3 or x=−4−3

or, x=1 or x=−7

Answer 2

X2+6x-7

x2-7x+1x-7

X(x-7)+1(x-7)

(X+1)(x-7)

X=-1

X=7