Question

splitting middle term :
2root 2xsquare -9x+ 5root2

Answer 1

Answer:

$x=\frac{5}{2\sqrt{2} } \\& \\ x=\sqrt{2}$

Step-by-step explanation:

 $2\sqrt{2} x^{2} -9x + 5\sqrt{2}$                [we need to find the factors of $2\sqrt{2} * 5\sqrt{2}$=20]

                                                          (factors of 20 : -4 ; -5)

 $2\sqrt{2} x^{2} -9x+5\sqrt{2} =0\\ 2\sqrt{2} x^{2} -4x -5x +5\sqrt{2} =0\\\\ 2\sqrt{2}x(x-\sqrt{2} ) -5(x-\sqrt{2} )=0\\ \\(2\sqrt{2}x -5) *(x-\sqrt{2} )=0$                    

 $x-\sqrt{2} =0\\ x=\sqrt{2}$            $2\sqrt{2}x-5=0 \\2\sqrt{2}x=5\\ \\x=\frac{5}{2\sqrt{2} }$