Question

Splitting Middle term x^2-8x-48

Answer 1

Answer:

Hii friend

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$<svg width="40" height="50" viewBox="0 0 100 100">\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <path fill="red" d="M92.71,7.27L92.71,7.27c-9.71-9.69-25.46-9.69-35.18,0L50,14.79l-7.54-7.52C32.75-2.42,17-2.42,7.29,7.27v0 c-9.71,9.69-9.71,25.41,0,35.1L50,85l42.71-42.63C102.43,32.68,102.43,16.96,92.71,7.27z"></path>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <animateTransform \ \textless \ br /\ \textgreater \ attributeName="transform" \ \textless \ br /\ \textgreater \ type="scale" \ \textless \ br /\ \textgreater \ values="1; 1.5; 1.25; 1.5; 1.5; 1;" \ \textless \ br /\ \textgreater \ dur="2s" \ \textless \ br /\ \textgreater \ repeatCount="40"> \ \textless \ br /\ \textgreater \ </animateTransform>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ </svg>$

Step-by-step explanation:

x² - 8x - 48

= x² - 2x - 6x - 48

=> x(x - 2) - 6 (x - 2)

= (x-2)( x - 6)

$<b><marquee>$Mark me as brainliest

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$<svg width="400" height="100" viewBox="0 0 100 100">\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <path fill="red" d="M92.71,7.27L92.71,7.27c-9.71-9.69-25.46-9.69-35.18,0L50,14.79l-7.54-7.52C32.75-2.42,17-2.42,7.29,7.27v0 c-9.71,9.69-9.71,25.41,0,35.1L50,85l42.71-42.63C102.43,32.68,102.43,16.96,92.71,7.27z"></path>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <animateTransform \ \textless \ br /\ \textgreater \ attributeName="transform" \ \textless \ br /\ \textgreater \ type="scale" \ \textless \ br /\ \textgreater \ values="1; 1.5; 1.25; 1.5; 1.5; 1;" \ \textless \ br /\ \textgreater \ dur="2s" \ \textless \ br /\ \textgreater \ repeatCount="40"> \ \textless \ br /\ \textgreater \ </animateTransform>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ </svg>$

Answer 2

$\huge\mathfrak\pink{hello~friends }$$<font color="green">$

$\huge{\fbox{\fbox{\orange{\mathfrak{Answer\:Given }}}}}$

$\huge\red{\underbrace{\overbrace{\ulcorner{\mid{\overline{\underline{From\:Above}}}}}}}$

$<font color=red>$

=>>> X² - 8x - 48

=>>> X² - ( 12- 4 )x - 48

=>>> X² - 12x + 4x - 48

=>>> X( x - 12 ) + 4 ( x - 12)

=>>> ( x + 4) ( x - 12)

Hope it's helps u

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