Question

Splitting the middle term 2x2-x+1/8=0 pls answer fast

Answer 1

Question

2x^2 - x + 1 / 8 = 0

16x^2 - x + 1 = 0

$\large \implies{d \: = \: {b}^{2} - 4ac = 0} \\ \\ \large \implies{( - 1) {}^{2} - 4(16)(1) = 0} \\ \\ \large \implies{1 \: - \: 64 = 0} \\ \\ \large \implies{ - 63 = 0} \\ \\ \large \implies{d \: < 0 \: \: roots \: \: are \: \: imaginary}$

Answer 2

$\tt\pink{Answer}$

$\tt{2x^2 - x + 1 / 8 = 0}$

$\tt{16x^2 - x + 1 = 0}$

$\tt{→D=b^2-4ac=0}$

$\tt{→(-1)2-4(16)(1)=0}$

$\tt{→1-64=0}$

$\tt{→-63=0}$

$\tt{→d<0\:roots\:are\:imaginary}$