Question

splitting the middle term
2x²+x-528=0​

Answer 1

Answer:

[math]2x^2 + x - 528 = 0[/math]

[math]2x^2 + 33x - 32x - 528 = 0[/math]

[math](2x^2 - 32x) + (33x - 528) = 0[/math]

[math]2x(x - 16) + 33(x - 16) = 0[/math]

[math](2x + 33)(x - 16) = 0[/math]

So do I need to solve it too?

Nah, I’ll do it…

[math]2x + 33 = 0[/math] or [math]x - 16 = 0[/math]

[math]x = -16,5[/math] or [math]x = 16[/math]

[math]x \in \{-16,5 ; 16 \}[/math]

Answer 2

Answer:

(x-16)(2x+33)=0

x=16

x=-33/2

Step-by-step explanation:

2x²+x-528

a=2

b=1

c=-528

product=a×c

Sum=b

product=2(-528)=-1056

sum=1

33×(-32)=-1056

33-32=1

2x²+33x-32x-528=0

x(2x+33)-16(2x+33)=0

(x-16)(2x+33)=0

x-16=0

x=16

2x+33=0

2x=-33

x=-33/2