Question

Splitting the middle term of x^2-11x+18

Answer 1

Answer:

${x}^{2} - 11x + 18 = 0 \\ = {x}^{2} - 9x - 2x + 18 = 0 \\ = x(x - 9) - 2(x - 9) = 0 \\ = (x - 9)(x - 2) = 0 \\ x = 9 \: \: and \: 2$

Hey! Mate Here is your solution. Thanks

Answer 2

$\huge\mathfrak\blue{Answer:}$

$\huge\orange{(x - 9)(x - 2)}$

Step-by-step explanation:

According to the Q,

$> > {x}^{2} - 11x + 18$

Sum = -11

Product = 18

$> > {x}^{2} - 9x - 2x + 18$

$> > x(x - 9) - 2(x - 9)$

$\orange {> > (x - 9)(x - 2)}$

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