Question

Splitting the middle term with roots X2+2root2x-6

Answer 1

$x ^{2} + 2 \sqrt{2}x - 6 = 0$

$x ^{2} + ( - 3 \sqrt{2} x + \sqrt{2} x) - 6 = 0$

$x^{2} - 3 \sqrt{2} x + \sqrt{2} x - 6 = 0$

$x(x - \sqrt{2} ) + 3 \sqrt{2} (x - \sqrt{2} ) = 0$

$(x - \sqrt{2} )(x + 3 \sqrt{2} ) = 0$

$x - \sqrt{2} = 0 or \:x - 3 \sqrt{2} = 0$

$x = \sqrt{2} orx = - 3 \sqrt{2}$