Math, asked by mehta06, 10 months ago

splitting the middle term

x^2+5x+6

x^2-5x+6

x^2+5x-6

x^2-5x-6

Answers

Answered by dangerousqueen01
30

Step-by-step explanation:

 {x}^{2}  + 5x + 6 \\  =  {x}^{2}  + 3x + 2x + 6 \\  = x(x + 3) + 2(x + 3) \\  = (x + 3)(x + 2)

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 {x}^{2}  - 5x + 6 \\  =  {x}^{2}  - 3x - 2x + 6 \\  = x(x - 3) - 2(x - 3) \\ (x - 3)(x - 2)

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 {x}^{2}  + 5x - 6 \\  =  {x}^{2}   + 6x  - x - 6 \\  = x(x  + 6)  -  1(x  +  6) \\  = (x  +  6)(x  -  1)

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 {x}^{2}  - 5x - 6 = \\  =  {x}^{2}  - 6x + x - 6 \\  = x(x - 6) + 1(x - 6) \\  = (x - 6)(x + 1)

Answered by Anonymous
4

 \huge{ \underline{ \bold{ᴀɴsᴡᴇʀ....{ \heartsuit}}}}

$$\begin{lgathered}{x}^{2} + 5x + 6 \\ = {x}^{2} + 3x + 2x + 6 \\ = x(x + 3) + 2(x + 3) \\ = (x + 3)(x + 2)\end{lgathered}$$

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$$\begin{lgathered}{x}^{2} - 5x + 6 \\ = {x}^{2} - 3x - 2x + 6 \\ = x(x - 3) - 2(x - 3) \\ (x - 3)(x - 2)\end{lgathered}$$

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$$\begin{lgathered}{x}^{2} + 5x - 6 \\ = {x}^{2} + 6x - x - 6 \\ = x(x + 6) - 1(x + 6) \\ = (x + 6)(x - 1)\end{lgathered}$$

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$$\begin{lgathered}{x}^{2} - 5x - 6 = \\ = {x}^{2} - 6x + x - 6 \\ = x(x - 6) + 1(x - 6) \\ = (x - 6)(x + 1)\end{lgathered}$$

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