Splitting the middle terms
2x^2+5x+3=0
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Answer:
2x^2+5x+3=0
2x^2+3x+2x+3=0
x(2x+3) +1(2x+3) =0
(x+1) (2x+3)
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Given is quadratic
1st find the factor of 2x3=6
we write it as,
1x6=6
2x3=6or3x2=6 that should be sum of the middle term of equation
so take it as 2+3or3+2
2x^2+2x+3x+3=0
now take common
2x(x+1)+3(x+1)=0
2x+3=0andx+1=0
therefore
x= -3/2,x=-1
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