Question

splitting the middle terms

Answer 1

a = 3, b = -3 ,c = 4

$d = b {}^{2} - 4ac$

$( - 3) {}^{2} - 4(3)(4)$

9- 48 = -39

Hence, d <0

So equation will have no real roots.

Answer 2

$3 {x}^{2} - 3x + 4$
No zeros exist as
B square - 4 a c is smaller than 0