Question

Splitting up the middle term of 2x^2+27x+25

Answer 1

given that

2x^2+27x+25=0

"by using splitting the middle term"

(2x^2+2x)+(25x+25)=0

2x(x+1) +25(x+1)=0

x+1=0 or 2x+25=0

x=-1. or. x=-25/2

Answer 2

Answer:

$(x + 1)(2x + 25)$

Step-by-step explanation:

$= 2x {}^{2} + 27x + 25 \\ = 2x {}^{2} + 2x + 25x + 25 \\ = 2x(x + 1) + 25(x + 1) \\ = (x + 1)(2x + 25) \: \: \: \: \ \: \: \: \: \: \: \: answer$