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Two pipes together can fill a tank in 12 hours. W the first pipe can
the tank 10 hours faster than the second then how many hours will the
second pipe take to fill the tank?
ater taps together fil
Answers
Explanation:
Two pipes together can fill a tank in 12 hours. Hence x is 30 hours
Explanation:
Let two pipes A and B are such that pipe takes x hours to fill the tank if working alone.
Then time taken by pipe A will be =x–5
So work done by pipe B in one hour =1x
And work done by pipe A in one hour =1x–5
Therefore work done by A and B together =1x–5+1x
Also A and B take 6 hours to fill the tank when working together.
So work done by A and B together will also be =16
A.T.Q.
1x–5+1x=16
Or x–5+xx(x–5)=16
Or 2x–5x2–5x=16
Multiplying both sides by 6(x2–5 x ) we get
6(2x–5)=1(x2–5x)
Or 12x–30=x2–5x
Or x2–17x+30=0
Or x2–15x–2x+30=0
Or x(x–15)–2(x–15)=0
Or (x–15)(x–2)=0
⇒ either x=15 or x=2
But x=2 is rejected as slower pipe takes more than 5 hours to fill the tank.
Thus slower pipe takes 15 hours and faster pipe takes 15–5=10 hours to fill the tank.