Question

spreadsheet, showing the atomic number, electronic configuration, valency and atomic mass number of He,B, S, Na, C, P and Cl

Answer 1

he. atomic no.2,elec.confi.2,2 , valency 2+
atomic mass no. 4

Answer 2

Explanation :

Element is, Helium (He)

Atomic number = 2

Atomic mass = 4 g/mole

Electronic configuration = $1s^2$

Valency : It is denoted for an element which can lose or gain the number of electrons.

Valency of Helium = 0

Element is, Boron (B)

Atomic number = 5

Atomic mass = 10 g/mole

Electronic configuration = $1s^22s^22p^1$

Boron can lose 3 electrons. So, the valency will be, 3

Element is, Sulfur (S)

Atomic number = 16

Atomic mass = 32 g/mole

Electronic configuration = $1s^22s^22p^63s^23p^4$

Sulfur can gain 2 electrons. So, the valency will be, 2

Element is, Sodium (Na)

Atomic number = 11

Atomic mass = 23 g/mole

Electronic configuration = $1s^22s^22p^63s^1$

Sodium can lose 1 electron. So, the valency will be, 1

Element is, Carbon (C)

Atomic number = 6

Atomic mass = 12 g/mole

Electronic configuration = $1s^22s^22p^2$

Carbon can gain 4 electrons. So, the valency will be, 4

Element is, Phosphorous (P)

Atomic number = 15

Atomic mass = 31 g/mole

Electronic configuration = $1s^22s^22p^63s^23p^3$

Phosphorous can gain 3 electrons. So, the valency will be, 3

Element is, Chlorine (Cl)

Atomic number = 17

Atomic mass = 35.5 g/mole

Electronic configuration = $1s^22s^22p^63s^23p^5$

Chlorine can gain 1 electron. So, the valency will be, 1