Physics, asked by kanika13, 1 year ago

spring constant of a spring in the figure shown is 100 N/m elongation in the spring is approximately

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Answered by JunaidMirza
21
Tension in the given string is
T = [2m1m2 / (m1 + m2)]g
= [2 × 4 × 2 / (2 + 4)] × 10
= 26.67 N

F = kx
T = kx
x = T / k
x = 26.67 / 100
x = 0.2667 m
x = 26.67 cm

Elongation in the spring is 26.67 cm
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