Question

​Spring constant of spring is 5 dyne cm–1 and it is elongated from 20cm to 22cm then energy stored in the spring is

Answer 1

Answer:

potential energy

Explanation:

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Answer 2

Given,

spring constant(k)=5dyne

X=2 because the question asked it elongated from 20cm to 22cm,so 22-20=2

Now,

Spring constant=1/2kx²

so,1/2×5×2²

=1/2×5×4

so,2×1=2 ,2×2=4 will be cancelled then answer will 10erg.

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