Physics, asked by dk7449359, 8 months ago

Spring constant of spring which has potential energy of 50 J when it is stretched through a
distance of 10 cm is
(A) 112 * 10 N/m
(B) 100 x 10' N/m
(C) 900 x 10' N/m
(D) 70 x 10' N/m

Answers

Answered by Anonymous

4

Answer:

50=1/2*k*0.1*0.1

k= 10000

option B will be the correct

Answered by sravya200430

3

Answer:

b option is right to that question

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