Question

Spring constant of spring which has potential energy of 50 J when it is stretched through a
distance of 10 cm is
(A) 112 * 10 N/m
(B) 100 x 10' N/m
(C) 900 x 10' N/m
(D) 70 x 10' N/m​

Answer 1

Answer:

50=1/2*k*0.1*0.1

k= 10000

option B will be the correct

Answer 2

Answer:

b option is right to that question