Spring mass system has a time period of 2 second what should be the spring constant of a spring if the mass of block is 10 grams
Answers
spring constant of spring is 10.13 × 10^-4 N/m
time period of spring mass system is given as, T = 2π√{m/K}
where m is mass, T is time period and K is spring constant.
here, time period, T = 2s
mass of block, m = 10g = 0.01kg
spring constant , k = ?
now, 2s = 2π√{0.01/k}
squaring both sides, we get
⇒4 = 4π² × 0.01/k
⇒k = 0.01/π² = 0.001013 N/m = 10.13 × 10^-4 N/m
hence, spring constant of spring is 10.13 × 10^-4 N/m
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time period of spring mass system is given as, T = 2π√{m/K}
where m is mass, T is time period and K is spring constant.
here, time period, T = 2s
mass of block, m = 10g = 0.01kg
spring constant , k = ?
now, 2s = 2π√{0.01/k}
squaring both sides, we get
⇒4 = 4π² × 0.01/k
⇒k = 0.01/π² = 0.001013 N/m = 10.13 × 10^-4 N/m
hence, spring constant of spring is 10.13 × 10^-4 N/m