Question

Spring mass system has a time period of 2 second what should be the spring constant of a spring if the mass of block is 10 grams

Answer 1

The time period of the spring is 0.098 N/m.

Explanation:

Given that,

Time period of the spring, T = 2 s

Mass of the block, m = 10 g = 0.01

The time period of the spring if the mass is attached to it is given by :

$T=2\pi\sqrt{\dfrac{m}{k}}$

$k=\dfrac{4\pi^2m}{T^2}$

$k=\dfrac{4\pi^2\times 0.01}{(2)^2}$

k = 0.098 N/m

So, the spring constant of the spring is 0.098 N/m. Hence, this is the required solution.

Learn more :

Topic : Time period of the spring

https://brainly.in/question/13454479