Economy, asked by rowenaguanzon, 7 months ago

spring scales should be adjusted so that pointer is at

Answers

Answered by pradeep48472o
15

Answer:

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Explanation:

A spring balance has a scale reading from 0 to 50 kg. The length of the scale is 20 cm. A body suspended to the spring balance when displaced and released oscillates with a period of 0.6 second. The mass off the body is:

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ANSWER

According to the question,

The maximum mass scale can read M=50kg

The maximum displcement of spring =

length of scale, l=20cm=0.2m

T (time period) =0.6s

Maximum force exerted on the spring F=mg

So,

g=acceleration due to gravity =9.8m/s

2

F=50×9.8=490

Since, speing constant,

k=

l

F

=

0.2

490

=2450Nm

−1

m is suspended from the balance

T=2π

k

m

Since,

m=(

T

)

2

×k

=(

2×3.14

0.6

)

2

×2450

≈22kg

Answered by itssaniyawadhwa02
0

Answer:Zero.

Explanation:

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