Question

sqaure. of any positive interger is of 7m 7m+1 7m+4 shaow that​

Answer 1

Answer:

tmit is same question from textbook only number is chan

Answer 2

Answer:

a=bq+r (EDL)

let b=7

a=7q+r (0<r<7)

r=0

a=7q+0

sobs

(a)^2=(7q)^2

(a)^2=49q^2

(a)^2=7(7q)^2

(a)^2=7m. [m=7q^2]

r=1

a=7q+1

sobs

(a)^2=(7q+1)^2

(a)^2=(7q)^2+2*7q*1+(1)^2

(a)^2=49q^2+14q+1

(a)^2=7(7q^2+2q)+1

(a)^2=7m+1. [m=7q^2+2q]

r=2

a=7q+2

sobs

(a)^2=(7q+2)^2

(a)^2=(7q)^2+2*7q*2+(2)^2

(a)^2=49q^2+28q+4

(a)^2=7(7q^2+4q)+4

(a)^2=7m+4. [m=7q^2+4q]

therefore, square of any positive integer is in the form of 7m,7m+1,7m+4.