sqaure root of.. -5 upon 11 is
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Answer:
here 'i' is an imaginary number having value
hope this answer is helpful to you
stay cool guys
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Step-by-step explanation:
(-5/11)^(1/2)
(5i/11)^(1/2)
i^(1/2)*0.45
0.45 * i^(1/2)
if you want to substitute I value
i^0=1 ,i=i i^2=-1,i^3=-i etc
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