/sqrt{1+cos theta}/1-cos theta=1/cosec theta-cot theta
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Answer:
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Step-by-step explanation:
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Step-by-step explanation:
I am using A in place of theta
sqrt{(1+cosA)/(1-cosA)
multiplying numerator and denominator with (1-cosA)
sqrt{(1+cosA)(1-cosA)/(1-cosA)(1-cosA)}
sqrt{(1-cos^2A)/(1-cosA)^2}
sqrt{sin^2A/(1-cosA)^2}
= sinA/(1-cosA)
dividing numerator and denominator by sinA
= (sinA/sinA)/(1-cosA)/sinA
= 1/(1/sinA) - cosaa/sinA
= 1/(cosecA - cotA)
= RHS proved
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