Math, asked by ayantika13, 6 hours ago

sqrt((1 + sin 60 degrees)/(1 - sin 60 degrees)) - sec(60 degrees) = sec(60 degrees) - sqrt((1 - sin 60 degrees)/(1 + sin 60 degrees))​

Answers

Answered by Rohit57RA
3

\sqrt{{1 + sin 60 degrees}/{1 - sin 60 degrees}} - sec{60 degrees} = sec{60 degrees} - sqrt{{1 - sin 60 degrees}/{1 + sin 60 degrees}}

Answered by SahabanAnsary
0

Answer:

Proved

Step-by-step explanation:LHS=

sqrt((1+sin60°/1-sin60°))-sec60°

=sqrt((1+√3/2)/1-√3/2)) -2

=sqrt(2+√3/2-√3) -2

RHS=sec60°-sqrt((1-sin60°/1+sin60°))

=2-sqrt((2-√3/2+√3))

=sqrt(2+√3/2-√3) -2

So, LHS=RHS(proved)

Similar questions