Question

sqrt(3) * (1 + tan 15 degrees) = 1 - tan 15 degrees .​

Answer 1

Answer:

(1+tan15)/(1-tan15)=(1+tan15)^2/(1-tan^2 15)=(1+2tan 15+tan^2 15)×cos^2 15/(cos^2 15-sin^2 15)=(cos^2 15+2sin 15×cos^2 15/cos 15+sin^2 15×cos^2 15/cos^2 15)/cos 30=(cos^2 15+sin^2 15+2sin 15.cos 15)×2/(3)^1/2=(1+sin30)2/(3)^1/2=(2+2.1/2)÷(3)^1/2=3÷(3)^1/2=(3)^1/2 ans.

Step-by-step explanation:

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