Math, asked by alok8589, 2 months ago

\sqrt [ 3 ] { ( \frac { 1 } { 64 } ) ^ { \frac { 1 } { 2 } } }​

Answers

Answered by koushikpaul06
1

Answer:

The solution is \sqrt [ 3 ] { ( \frac { 1 } { 64 } ) ^ { \frac { 1 } { 2 } } } is \frac{1}{2}

Step-by-step explanation:

We know that \sqrt{x} = x^{\frac{1}{2} } and \sqrt [ 3 ] { x   } } } = x^{\frac{1}{3} }

Now, \frac{1}{64} can be written as (\frac{1}{2})^{6}.

According to question,

⇒  \sqrt [ 3 ] { ( \frac { 1 } { 64 } ) ^ { \frac { 1 } { 2 } } }

\sqrt [ 3 ] { ( \frac { 1 } { 2} )^{6}^ { \frac { 1 } { 2 } } }

{ ( \frac { 1 } { 2} )^{3 } } }^{\frac{1}{3} }

(\frac{1}{2})^{1}

\frac{1}{2}

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