Question

(sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2))=a+bsqrt(6)

Answer 1

see the image

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Answer 2

Step-by-step explanation:

$\frac{ \sqrt{3 } + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } . \\ \\ = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} \times \sqrt{2} } . \\ \\ = \frac{ {( \sqrt{3} + \sqrt{2} )}^{2} }{3 - 2} . \\ \\ = 3 + 2 + 2 \sqrt{6} . \\ \\ = 5 + 2 \sqrt{6} = a + b \sqrt{6} .$

Hence, a = 5 and b = 2 .