Question

\sqrt[4]{81}-6(\sqrt[3]{216})+12(\sqrt[5]{32})+\sqrt{225}=​

Answer 1

Answer:

$\sqrt[4]{81}-6(\sqrt[3]{216})+12(\sqrt[5]{32})+\sqrt{225} \\ = { ({3}^{4} )}^{ \frac{1}{4} } - 6 { ({6}^{3}) }^{ \frac{1}{3} } + 12 { ({2}^{5} )}^{ \frac{1}{5} } + { ({15}^{2} )}^{ \frac{1}{2} } \\ = 3 - 6 \times 6 + 12 \times2 + 15 \\ = 3 - 36 + 24 + 15 \\ = 6 \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$