(sqrt(5)+sqrt(3))/(sqrt(5)-sqrt(3))=a+bsqrt(15)
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we have,
√5+√3/√5-√3=a+b√15
by rationalisation we get,
(√5+√3/√5-√3) × (√5+√3/√5+√3) = a+b√15
or, (√5+√3)²/ (5-3)= a+b√15
or, (5+3+2√15)/ 2= a+b√15
or, (8+2√15)/ 2= a+b√15
or, 8/2+2√15/2= a+b√15
or, 4+ √15= a+b√15
or, a= 4 and b = √15/√15
or, a = 4 and b= 1 ans.
if you have any problem then message me.
√5+√3/√5-√3=a+b√15
by rationalisation we get,
(√5+√3/√5-√3) × (√5+√3/√5+√3) = a+b√15
or, (√5+√3)²/ (5-3)= a+b√15
or, (5+3+2√15)/ 2= a+b√15
or, (8+2√15)/ 2= a+b√15
or, 8/2+2√15/2= a+b√15
or, 4+ √15= a+b√15
or, a= 4 and b = √15/√15
or, a = 4 and b= 1 ans.
if you have any problem then message me.
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Rationalise all the equation and u will get the value of a and b in each case
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