Question

sqrt(5-x^2) = x-1
How this can be solved

Answer 1

Answer:

tan-1 [x2+x]1/2 + sin-1 [x2+x+1]1/2 = pi/2

= tan-1[x2+x]1/2 + sin-1 [x2+x+1]1/2 = sin-1 [x2+x+1]1/2 + cos-1 [x2+x+1]1/2

= tan-1 [x2+x]1/2 = cos-1 [x2+x+1]1/2

= cos-1[1/ (x2+x+1)1/2] = cos-1[x2+x+1]1/2

= 1/ (x2+x+1)1/2 = [ x2+x+1]1/2

= x2+x+1 = 1

= x2+x = 0

=x(x+1)  =>  x=0 or x = -1

hope this is Helpful for you ..

please mark as brilliancy....

Answer 2

Step-by-step explanation:

answer is in the above attachment

the question has been solved by factorization of quadratic polynomial