sqrt(5 - x) > x + 1
What is the answer?
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Answer:
Given:
√(5-x) > (x+1).
Squaring on both sides, we get,
(5-x) > (x+1)².
That is,
(5-x) > x² + 1 + 2x.
Transposing (5-x) to the other side,
0 > x² + 1 + 2x - 5 + x.
0 > x² + 3x - 4.
Solving the quadratic equation, we get,
0 > x² + 4x - x - 4.
0 > x(x+4) -1(x+4).
0 > (x+4)(x-1).
So,
0 > (x+4) ,OR, 0 > (x-1).
-4 > x ,OR, 1 > x.
Therefore,
→ X can be lesser than (-4), or,
→ X can be lesser than 1.
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