Question

square ABCD of diagonal 2a is folded along the diagonal AC so that the planes DAC and BAC are at right angle. The shortest distance between DC and AB is

Answer 1

Answer:

When folded coordinates will be D(0,0,a);C(a,0,0);A(−a,0,0);B(0,−a,0)

Equation of DC is,

a

x

​

=

b

y

​

=

a

z−a

​

Equation of AB is,

a

x+a

​

=

−a

y

​

=

0

z

​

∴ Shortest distance =

3

​

2a

​

.

Step-by-step explanation:

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