square ABCD of diagonal 2a is folded along the diagonal AC so that the planes DAC and BAC are at right angle. The shortest distance between DC and AB is
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Answer:
When folded coordinates will be D(0,0,a);C(a,0,0);A(−a,0,0);B(0,−a,0)
Equation of DC is,
a
x
=
b
y
=
a
z−a
Equation of AB is,
a
x+a
=
−a
y
=
0
z
∴ Shortest distance =
3
2a
.
Step-by-step explanation:
Hope it helped u
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