Question

Square coil of side 10 cm consists of 20 terms and carries a current of 12 ampere the coil is suspended vertically and the normal to the plane of the coil makes an angle of 30 degree with the direction of a uniform horizontal magnetic field of magnitude 0.80 tesla what is the magnitude of torque experienced by the coil

Answer 1

Answer:

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A square coil of sides 10cm consists of 20 turns and carries a current of 12A . The coil is suspended vertically and the normal to 30∘ with the direction of a uniform horizontal magnetic field of magnitude 0.80T . What is the magnitude of torque experienced by the coil ?

0.96Nm−10.96Nm20.96N−m0.96Nm−2

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A)

Solution :

Given , side of the square coil =10cm=0.1m

Number of turns n=20

I=12A

θ=30∘

B=0.80T

T=NIABsinθ

T=20×12×(10×10−2)2×0.80×sin30∘

=20×12×(10×10−2)2×0.80×12

=0.96N−m

Answer : 0.96N−m

Answer 2

Answer:

ok right but but the unit of this and that is not metre Newton