Square each of side 8 centimetre are cut off from the four corners of a sheet of 10 measuring 48 cm by 36 cm the remaining portion of the sheet is holding to form a tank open at the top what will be the capacity of the tank
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base of box = original area - height of flaps
= (42-6-6)*(30-6-6) ---[ as there are 2 lengthwise flaps and 2 breadthwise ]
= 30 * 18
= 540 cm²
volume of box = base area * height
= 540 * 6
= 3240 cm³
= (42-6-6)*(30-6-6) ---[ as there are 2 lengthwise flaps and 2 breadthwise ]
= 30 * 18
= 540 cm²
volume of box = base area * height
= 540 * 6
= 3240 cm³
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