Question

Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H′. The square stretches with respect to the x-axis. If point H is located at (-2, 0), what are the coordinates of H′ ? A. (-5, 0) B. (-2, 0) C. (0.5, 0) D. (-2, 2.5)

Answer 1

Answer:

The answer is A. (-5, 0)

Step-by-step explanation:

It is given in the question that

⇒ EFGH stretches vertically

⇒ The fator by which it stretches is 2.5

⇒The resultant square is E′F′G′H′

Now it is mentioned in the question that the Square stretches with respect to x-axis.

It means that change will occur in x-coordinate only

The x-coordinate of (-2,0) is -2 which when stretches by 2.5 gives a value of -5.

So the right answer is (-5,0)