Question

Square garden is 100 m long path 10 metre wide runs around it inside find the area of the path and cost of travelling it at 5 paise per square metre​

Answer 1

Answer:

Given inner side of square park, s=100 cm

Given inner side of square park, s=100 cm Area of inner square =100

Given inner side of square park, s=100 cm Area of inner square =100 2

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cm

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm 2

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm 2

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm 2 Cost of cementing at the rate of Rs 250 per 10 sq cm = Rs 250×210= Rs 52500

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm 2 Cost of cementing at the rate of Rs 250 per 10 sq cm = Rs 250×210= Rs 52500∴ Cost of cementing a 2100 cm

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm 2 Cost of cementing at the rate of Rs 250 per 10 sq cm = Rs 250×210= Rs 52500∴ Cost of cementing a 2100 cm 2

Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm 2 Cost of cementing at the rate of Rs 250 per 10 sq cm = Rs 250×210= Rs 52500∴ Cost of cementing a 2100 cm 2 path =Rs. 52500

Answer 2

Step-by-step explanation:

side of garden =100m

area of garden = side ×side

= 100×100

= 10000m^2

side of garden without path= 100-10 = 90m

area of garden inside path = side ×side

= 90×90

= 8100m^2

area of path= area of garden - area of garden inside part

= 10000 - 8100

= 1900m^2

cost = rate × area

= 5 × 1900

=9500 paise

Rs 9500/100 = Rs 95