Question

square lead slab of Side 50cm and thickness 10 cm subjected to shearing force of 9 into 10 ^ 4 newton calculate the shearing stress acting on the slab​

Answer 1

Answer:

stress is basically a pressure.

shearing stress = F/ A ( force / area )

( area = top of the square slab is considered.)

so area = 50×50 ×10^-4 m²=25×10^-2 m²=0.25m²

= 1/4 m²

9× 10^4

shearing stress= ---------- = 36× 10^4 Nm^-2.

1/4

hope it helps ., thankyou.