Question

(square method)
x²+4x+4=0​

Answer 1

Step-by-step explanation:

x²+4x+4=0

=>x²+(2+2)x+4=0

=>x²+2x+2x+4=0

=>x (x+2)+2(x+2)=0

=>(X+2)(X+2)=0

X+2=0

=>X =2

Answer 2

Answer:

Hii mate!

here is your answer

${x}^{2} + 4x + 4 = 0$

${x}^{2} + (2 + 2)x + 4 = 0$

${x}^{2} + 2x + 2x + 4 = 0$

$x(x + 2) + 2(x + 2) = 0$

$(x + 2)(x + 2) = 0$

$x + 2 = 0$

$x = 2$