Question

Square of difference between two numbers is 9 while the sum of squares of those two numbers is 225. What is their product?

Answer 1

Let two numbers be x and y.
It is given that:
(x-y)²=9
x²+y²=225.
x.y=?
.·. x²+y²-2xy=9
.·.225-2xy=9.
.·.-2xy=-216
.·.xy=108.

So,their product is 108.

Answer 2

Their product is 108.

Step-by-step explanation:

Since we have given that

Square of difference between two numbers is 9.

Let the first number be 'x'.

Let the second number be 'y'.

So, it becomes,

$(x-y)^2=9---(1)$

the sum of squares of those two numbers is 225.

$x^2+y^2=225-------(2)$

Now, using (1), we get that

$(x-y)^2=9\\\\x^2+y^2-2xy=9\\\\225-2xy=9\\\\225-9=2xy\\\\216=2xy\\\\xy=\dfrac{216}{2}\\\\xy=108$

Hence, their product is 108.

# learn more:

The sum of the squares of three numbers is 175 while the sum of their products taken two at a time is 225. their sum is

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