Question

square of son's age. Find son's age today. Two dice are rolled simultaneously. Find the probability of following events. .

i) Event A: The sum of digits on the upper faces is at least 10.
ii) Event B: The sum of digits on the upper faces is divisible by 5. .
iii) Event C: The digit on the upper face of first die is greater than that on the second die

PLEASE GIVE THE RIGHT ANSWER​

Answer 1

For total number of outcomes please refer to the image

Therefore, total number of outcomes = 36

Event A :-

sum of the digits on the upper faces is at least 10

A= {(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)}

total number of favourable outcome = 6

Since, Probability =

$\frac{favourable \: outcome}{total \: outcome}$

therefore, 6/36 = 1/6

Hence, the probability that the sum of the digits on the upper faces is at least 10 is 1/6

Event B :-

The sum of digits on the upper faces is divisible by 5

B = {(1,4),(2,3),(3,2),(4,1),(4,6),(5,5),(6,4)}

total number of favourable outcome = 7

therefore, 7/36

Event C:-

The digit on the upper face of first die is greater than that on the second die

C = {(2,1),(3,1),(3,2),(4,1),(4,2),(4,3),(5,1),(5,2),(5,3),(5,4),(6,1),(6,2),(6,3),(6,4),(6,5)}

total number of favourable outcome = 15

therefore, 15/36