Question

square of (x-1/x) will be?​

Answer 1

Answer :-

${( \frac{x - 1}{x}) }^{2}$

$\frac{ {x}^{2} - 2x + 1}{ {x}^{2} }$

$\frac{(x - 1)(x - 1)}{{x}^{2} }$

Answer 2

Concept:

We need to know the following formula:

$(a-b)^{2}=a^{2}+b^{2}-2ab$

Given:

The following equation is given to solve

$(\frac{x-1}{x})^{2}$

To find:

We need to find the value of the above equation.

Solution:

Lets solve the above equatiom,

$(\frac{x-1}{x})^{2}$

⇒$\frac{(x-1)^{2} }{x^{2} }$

⇒$\frac{x^{2}-2x+1 }{x^{2} }$

⇒$\frac{x^{2} }{x^{2} } -\frac{2x}{x^{2} }+\frac{1}{x^{2} }$

⇒$1-\frac{2}{x} +\frac{1}{x^{2} }$

Therefore the solution to the above equation is $1-\frac{2}{x} +\frac{1}{x^{2} }$.