Math, asked by 7876233878, 8 months ago

(square root 2a +8b-sqare root 3c)^2​

Answers

Answered by adityarajverma682
1

Answer:

(√2a+8b - √3c)² :• (a-b)² = a²+b²-2ab

[ (√2a+8b)² + (√3c)² - 2(√2a+8b)(√3c) ]

[ (2a+8b) + (3c) - 2(6ac+24bc)]

[ 2a+ 8b + 3c -(12ac + 48bc)]

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