Question

square root 3 tan ø - 3=0 , find sin square ø minus cos square ø ​

Answer 1

Answer:

The sides of the triangle have been relabeled in reference to angle theta (Ø), where hyp is the hypotenuse, opp is the side opposite angle theta, and adj is the side adjacent to angle theta.

Answer 2

Answer:

0.5

Step-by-step explanation:

$\sqrt{3}$ tan∅ -3 =0

tan∅ =$\sqrt{3}$

sin∅/cos∅ =$\sqrt{3}$

so,   sin∅=$\frac{\sqrt{3}}\sqrt{[[\sqrt{3}]^{2}+[1]^{2}]$ = $\frac{\sqrt{3} }{2}$.

and cos∅ = $\frac{1}{2}$.

Therefore, $sin^{2}$∅ -$cos^{2}$∅ = $\frac{3}{4}$ - $\frac{1}{4}$ =$\frac{1}{2}$.