Question

Square root 45-3 square root 20+4 square root 5

Answer 1

Answer:

$\sqrt{45} - {3}^{2} \sqrt{20} + {4}^{2} \sqrt{5} = \\ \\ \\ = > \sqrt{5 \times 9} - 9 \sqrt{5 \times 4} + 16 \sqrt{5} \\ \\ \\ = > 3 \sqrt{5} - 18 \sqrt{5} + 16 \sqrt{5} \\ \\ \\ = > \sqrt{5} (3 - 18 + 16) \\ \\ \\ = > \sqrt{5} (19 - 18) \\ \\ \\ = > \sqrt{5} \times 1 \\ \\ \\ = = > > \sqrt{5} \: \: ans...$

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Answer 2

Answer:

√5

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