Math, asked by vaishnavireddy5261, 8 months ago

(square root 7-4root3)+(square root of 7+4root3)

Answers

Answered by priya191794
0

Answer:

Step-by-step explanation:

Let square root of 7–4.(3)^1/2 is +/-(x^1/2 -y^1/2).

[+/-(x^1/2-y^1/2)]^2=7 -4 .3^1/2

x+y-2.x^1/2.y^1/2= 7 -4.3^1/2

Equating the both sides.

x + y = 7…………(1)

x^1/2.y^1/2 = 2.3^1/2

or x.y = 12…………..(2)

On solving eq.(1) & (2)

x= 4 or 3

y = 3 or 4.

Therefore square root of 7–4.3^1/2 is:-

+/-(2–3^1/2) Answer.

Answered by Anonymous
3

Answer:

-12

Step-by-step explanation:

To Evaluate:

(√7 - 4√3) (√7 + 4√3)

Identity Used:

(a-b) (a+b) = a² - b²

Solution:

(√7 - 4√3) (√7 + 4√3)

= (√7)² - (4√3)²

= (√7 × √7) - (4 × 4 + √3 × √3)

= (7) - (16 + 3)

= 7 - 19

= -12

Hope it helps you......

Similar questions