square root 7 x squared minus 6 x minus 13 square root seven equals to zero solved using quadratic formula
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Hi ,
It is given that ,
√7x² - 6x - 13√7 = 0
splitting the middle term , we get
√7 x² -13x + 7x - 13√7 = 0
√7 x² - 13x + √7 × √7 x - 13√7 = 0
x( √7x - 13 ) + √7( √7x - 13 ) = 0
( √7x - 13 )( x + √7 ) = 0
√7x - 13 = 0 or x + √7 = 0
√7x = 13 or x = -√7
x = 13/√7 or x = -√7
I hope this helps you.
: )
It is given that ,
√7x² - 6x - 13√7 = 0
splitting the middle term , we get
√7 x² -13x + 7x - 13√7 = 0
√7 x² - 13x + √7 × √7 x - 13√7 = 0
x( √7x - 13 ) + √7( √7x - 13 ) = 0
( √7x - 13 )( x + √7 ) = 0
√7x - 13 = 0 or x + √7 = 0
√7x = 13 or x = -√7
x = 13/√7 or x = -√7
I hope this helps you.
: )
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