Question

square root of 0.289 / 0.00121

Answer 1

$\textbf{To find:}$

$\textbf{Square root of \dfrac{0.289}{0.00121} }$

$\textbf{Solution:}$

$\textbf{It is clear that,}$

$\bf\sqrt{289}=17$

$\bf\,\sqrt{121}=11$

$\text{Consider,}$

$\sqrt{\dfrac{0.289}{0.00121}}$

$=\dfrac{\sqrt{0.289}}{\sqrt{0.00121}}$

$=\dfrac{\sqrt{\dfrac{289}{1000}}}{\sqrt{\dfrac{121}{100000}}}$

$=\dfrac{\dfrac{\sqrt{289}}{\sqrt{1000}}}{\dfrac{\sqrt{121}}{\sqrt{100000}}}$

$=\dfrac{\sqrt{289}}{\sqrt{1000}}{\times}\dfrac{\sqrt{100000}}{\sqrt{121}}$

$=\dfrac{\sqrt{289}}{\sqrt{1000}}{\times}\dfrac{\sqrt{1000}\sqrt{100}}{\sqrt{121}}$

$=\sqrt{289}{\times}\dfrac{\sqrt{100}}{\sqrt{121}}$

$=17{\times}\dfrac{10}{11}$

$=\dfrac{170}{11}$

$=15.45$

$\therefore\textbf{Square root of \bf\dfrac{0.289}{0.00121} is 15.45}$

Find more:

Find the value of √3136 and use it to find the value of √31.36 + √0.3136

https://brainly.in/question/5760458

Answer 2

Answer : 15.45 is the answer